(unsigned) weights (powers of two)
4096 2048 1024  512  256  128   64   32   16    8    4    2    1

 1111 1101 0111 0110(b) = ? decimal

 Note: the left-most bit is "on", so this is a negative value.
 We can't directly convert negative values.
 We first make the value positive, and convert that.

 To convert a negative bit pattern to positive, we can either subtract
 it from 0, or reverse (flip) all the bits and add 1.  Let's flip and add:

 Negative:   1111 1101 0111 0110
 flip bits:  0000 0010 1000 1001
 add one:   +                  1
             -------------------
 Positive:   0000 0010 1000 1010

 Now add up the powers of two that make up this positive binary value:

    0000 0010 1000 1010 = 2^9 + 2^7 + 2^3 + 2^1
                        = 512 + 128 +  8  +  2 = 650 decimal

 This positive value is as positive as the negative number was negative.
 Therefore, the original negative number must be the minus of this value:

 1111 1101 0111 0110(b) = -650(d)

----

 0000 0001 0110 0000(b) = ? decimal

 Note: the left-most bit is "off", so this is a positive value.
 We do not need to do any bit flipping.  Just convert it to decimal
 by adding up powers of two:

    0000 0001 0110 0000(b) = 2^8 + 2^6 + 2^5
                           = 256 +  64 +  32
                           = +352(d)

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